[QMSE] W02 - Two Slit Diffraction
young’s slits
- two slits at a distance \( s \) are made in a mask
- then a wave is passed through a slit
- for large waves:
- the waves are approximately uniformly “bright”
- using exponential waves for convenience
- \( \psi_s(x) \propto \exp{ \left[ ik \sqrt{ \left( \frac{x-s}{2} \right)^2 + z_0^2 } \right] } + \exp{ \left[ ik \sqrt{ \left( \frac{x+s}{2} \right)^2 + z_0^2 } \right] }\)
- the waves are approximately uniformly “bright”
- approximate formulas for the distance gives
- \( \psi_s(x) \propto \exp{(i\alpha)} \left( \exp\left[ ik \left( \frac{sx}{2z_0} \right) \right] + \exp\left[ -ik \left( \frac{sx}{2z_0} \right) \right] \right) \)
- \( \alpha = k\left( z_0 + \frac{x^2}{2z_0} + \frac{s^2}{8z_0} \right) \)
- applying \( \exp{}-\cos{} \) relationship
- \( \psi_s(x) \propto \exp{(i\alpha)} \cos\left( \frac{ksx}{2z_0} \right) \)
- intensity of the beam
- \( \lvert \psi_s (x) \rvert^2 \propto \cos^2 = \frac{1}{2} \left[ 1 + \cos{\left( \frac{2\pi sx}{\alpha z_0} \right) } \right] \)
interpreting diffraction by two slits
-
in the quantum mechanics paradigm, there is no specific size to the photon or electron
- the act of the electron or photon hitting the screen causes a measurement to be made
- the wavefunction collapses into one with a definite position
- whose probability is given by the born’s rule
- the wavefunction collapses into one with a definite position
- the establishment of which slit the electron goes through is meaningless
- we can either have the interference pattern or know which slit the electron went through